A 25.00-mL sample of propionic acid, HC 3 H 5 O 2 , of unknown concentration was

Question

A 25.00-mL sample of propionic acid, HC3H5O2, of unknown concentration was titrated with 0.171 M KOH. The equivalence point was reached when 43.54 mL of base had been added. What is the hydroxide-ion concentration at the equivalence point? Ka for propionic acid is 1.3 A 25.00-mL sample of propionic acid, HC3H5O2, of unknown concentration was titrated with 0.171 M KOH. The equivalence point was reached when 43.54 mL of base had been added. What is the hydroxide-ion concentration at the equivalence point? Ka for propionic acid is 1.3 A 25.00-mL sample of propionic acid, HC3H5O2, of unknown concentration was titrated with 0.171 M KOH. The equivalence point was reached when 43.54 mL of base had been added. What is the hydroxide-ion concentration at the equivalence point? Ka for propionic acid is 1.3

Explanation / Answer

total volume after titration = 0.0685 L (0.025+0.0435)
moles KOH = 0.171 x 0.04354 L=0.00744
[C3H5O2-] = 0.00744 / 0.0685 =0.1087 M

C3H5O2- + H2O <------> HC3H5O2 + OH-
Kb = Kw/Ka = 7.7 x 10^-10 = x^2 / 0.1087-x

x = [OH-]= 9.1 x 10^-6 M

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