1- What size tank would be needed to contain this same amount of helium at atmos

Question

1-What size tank would be needed to contain this same amount of helium at atmospheric pressure (1 atm)?

When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction CaCO3 (s) rightarrow CaO(s)+ CO2 (g) What is the mass of calcium carbonate needed to produce 51 .OL of carbon dioxide at STP? Express your answer with the appropriate units. Butane, C4H10, is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete combustion of butane is 2C4H10 (g) +1302 (g)rightarrow 8C02 (g) + 10H20(l) At 1.00 atm and 23 degree C, what is the volume of carbon dioxide formed by the combustion of 1.00g of butane? Express your answer with the appropriate units.

Explanation / Answer

Moles of CO2 = 51/44

= 1.159 moles

Moles of CaCO2 needed = 1.159 moesl

Therfore mass = 10*1.159

= 115.9 g

Moles of Butane needed = 1/58

= 0.0172 moles

Moles of CO2 formed = 4*0.0172

= 0.0689 moles

PV = nRT

1*V = 0.0689*0.0821*(273+23)

V = 1.675 liter

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