The rate law for the reaction 2NO(g) + Br 2 (g) ? 2NOBr(g) is rate = k[NO] 2 [Br

Question

The rate law for the reaction

2NO(g) + Br2(g) ? 2NOBr(g)

is rate = k[NO]2[Br2]. How would the initial rate change if the concentration of NO was doubled? possible answers but please show work and explain: The initial rate would increase by a factor of four. The initial rate would double. The initial rate would increase by a factor of three. The initial rate would not change. The rate law for the reaction

2NO(g) + Br2(g) ? 2NOBr(g)

is rate = k[NO]2[Br2]. How would the initial rate change if the concentration of NO was doubled? The rate law for the reaction

2NO(g) + Br2(g) ? 2NOBr(g)

is rate = k[NO]2[Br2]. How would the initial rate change if the concentration of NO was doubled? The initial rate would increase by a factor of four. The initial rate would double. The initial rate would increase by a factor of three. The initial rate would not change. The initial rate would increase by a factor of four. The initial rate would double. The initial rate would increase by a factor of three. The initial rate would not change. The initial rate would increase by a factor of four. The initial rate would double. The initial rate would increase by a factor of three. The initial rate would not change.

Explanation / Answer

rate is directional propotional to squere of concentration of NO so if the concentration of NO was doubled then rate will increase by factor of 4

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