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In the following net ionic equation, identify each species as either a Br In the

ID: 799704 • Letter: I

Question

In the following net ionic equation, identify each species as either a Br

In the following net ionic equation, identify each species as either a Br nsted-Lowry acid or a Br nsted-Lowry base. HSO_3- (aq) + HNO_2 (aq) rightarrow H_2SO_3 (aq) + NO_2- (aq) In this reaction: the formula for the conjugate (acid or base) HSO_3- is ? the formula for the conjugate (acid or base) of HNO2 is ? In the following net ionic equation, identify each species as either a Br nsted-Lowry acid or a Br nsted-Lowry base. In this reaction: the formula for the conjugate (acid or base) of NO2- is the formula for the conjugate (acid or base) of HCO3- is

Explanation / Answer

1) A bronsted is acid is the one which donates a proton ( H+) and bronsted base is the one which accepts a proton .


SO from the given reaction


  HSO_3- (aq) + HNO_2 (aq) -------> H_2SO_3 (aq) + NO_2- (aq)


here No2 is donating the proton .So it is bronsted lowry acid .


Hs03- is acepting a proton .So it is a bronsted lowry base .


Removing a proton from a bronsted acid gives a conjugate base .


So N02- is a conjugate base


adding a proton to a bronsted base gives a conjugate acid


So H2S03 is the conjugate acid .



HN02 ----> bronsted acid


HS03- ----> bronsted base


N02- ----> bronsted base


H2S03 -----> bronsted acid



2) N02- + Hc03- ------> HN02 + C032-



here HC03- is donating the proton .So it is bronsted lowry acid .


N02 is acepting a proton .So it is a bronsted lowry base .


Removing a proton from a bronsted acid gives a conjugate base .


So C032- is a conjugate base


adding a proton to a bronsted base gives a conjugate acid


So HN02 is the conjugate acid .



So HC03- ----> bronsted acid


N02 ----> bronsted base


C032- ----> bronsted base


HN02 -----> bronsted acid

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