In the following net ionic equation, identify each species as either a Br In the
ID: 799705 • Letter: I
Question
In the following net ionic equation, identify each species as either a Br
In the following net ionic equation, identify each species as either a Br nsted-Lowry acid or a Br nsted-Lowry base. HSO_3- (aq) + HNO_2 (aq) rightarrow H_2SO_3 (aq) + NO_2- (aq) In this reaction: the formula for the conjugate (acid or base) HSO_3- is ? the formula for the conjugate (acid or base) of HNO2 is ? In the following net ionic equation, identify each species as either a Br nsted-Lowry acid or a Br nsted-Lowry base. In this reaction: the formula for the conjugate (acid or base) of NO2- is the formula for the conjugate (acid or base) of HCO3- isExplanation / Answer
1) A bronsted is acid is the one which donates a proton ( H+) and bronsted base is the one which accepts a proton .
SO from the given reaction
HSO_3- (aq) + HNO_2 (aq) -------> H_2SO_3 (aq) + NO_2- (aq)
here No2 is donating the proton .So it is bronsted lowry acid .
Hs03- is acepting a proton .So it is a bronsted lowry base .
Removing a proton from a bronsted acid gives a conjugate base .
So N02- is a conjugate base
adding a proton to a bronsted base gives a conjugate acid
So H2S03 is the conjugate acid .
HN02 ----> bronsted acid
HS03- ----> bronsted base
N02- ----> bronsted base
H2S03 -----> bronsted acid
2) N02- + Hc03- ------> HN02 + C032-
here HC03- is donating the proton .So it is bronsted lowry acid .
N02 is acepting a proton .So it is a bronsted lowry base .
Removing a proton from a bronsted acid gives a conjugate base .
So C032- is a conjugate base
adding a proton to a bronsted base gives a conjugate acid
So HN02 is the conjugate acid .
So HC03- ----> bronsted acid
N02 ----> bronsted base
C032- ----> bronsted base
HN02 -----> bronsted acid
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