C O ( g ) + 2 H 2 ( g ) ? C H 3 O H ( g ) The equilibrium constant for this reac
ID: 799971 • Letter: C
Question
CO(g)+2H2(g)?CH3OH(g)
The equilibrium constant for this reaction at 25
?C is Kc = 2.3*10^4 part A ) Kc = [CH3][OH]/[CO][H2]^2 part B =
[CH3OH] = Kc[CO][H2]^2 Suppose that the molar concentrations for
Use the formula you found in Part B to calculate the concentration of CH3OH. = 2.5 M
The reaction is at equilibrium, so the concentrations will not change. The forward reaction will be favored until equilibrium is reached. The reverse reaction will be favored until equilibrium is reached.Explanation / Answer
Given,
[CH3OH] = 2
[CO] = 2
[OH] = 2 : [OH]^2 = 4
Qc=[CH3OH]/[CO][OH]^2
Qc=2/(2)(4)
Qc=1/4
Qc is less than Kc.
The products concentration is less than that of the reactants
Therefore,The forward reaction will be favored until equilibrium is reached.
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