The following pressure data was recorded for a chamber, initially charged with b

Question

The following pressure data was recorded for a chamber, initially charged with butadiene, during a reaction following its gas-phase dimerization at some constant temperature. Derive an expression relating the partial pressure of butadiene to the total pressure, and determine the order of the reaction and the value of the rate constant. (The rate law may be expressed using partial pressures instead of concentraitons.)

The following pressure data was recorded for a chamber, initially charged with butadiene, during a reaction following its gas-phase dimerization at some constant temperature. Derive an expression relating the partial pressure of butadiene to the total pressure, and determine the order of the reaction and the value of the rate constant. (The rate law may be expressed using partial pressures instead of concentrations.)

Explanation / Answer

a) the reaction equation is

2*Butadiene -----> (butadiene)2

so let the initial pressure of butadiene be Po.

let the amount dissociated be x.so,

pressure of butadiene=Po-x

pressure of (butadiene)=0.5x

total pressure=Po-x+0.5x

=Po-0.5x

so total pressure=po-0.5x

Pressure of butadiene=Po-x

b)Now if we plot the graph for this,,

for we find that 1/[A] =kt-1/[Ao] comes a stright line (you need to check for first and zero order too)

so, the reaction is second order with respect to butadiene.

and the rate equation is

Rate=k*[butadiene]^2

also,

for the value of rate constant,

1/(0.8138)=k*3.25 + 1/(0.8315)

or k=8*10^-3 M^-1 min

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