The hydrolysis of ethyl acetate (CH3COOC2H5) by sodium hydroxide yields ethanol

Question

The hydrolysis of ethyl acetate (CH3COOC2H5) by sodium hydroxide yields ethanol (C2H5OH) and sodium acetate (NaO2CCH3) by the reaction shown, which follows second order kinetics.  In an experiment 500 mL of 0.1 M ethylacetate in water is mixed with 500 mL of 0.1 M NaOH in water.  After 20 minutes the concentration of sodium acetate is measured and is 0.0435M.  Determine the rate constant for the reaction.
CH3COOC2H5  +  NaOH   C2H5OH  +  NaO2CCH3

A) 0.002 L mol-1s-1   B) 0.11 s-1   C) 0.11 L mol-1 s-1   D) 0.3 L mol-1 s-1     E) 0.5 L mol-1 s-1

Explanation / Answer

For similar [A]0 and [B]0 (Initial concentrations of reactants)

1/[A] = 1/[A]0 + kt

1/.0435 = 1/.1 + 1200k

22.98 = 10 + 1200k

12.98 = 1200k

k = 0.011 L mol-1 s-1

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.