Given the rate equation... RATE = ([ Na 2 S 2 O 3 ]/time) = k [I - ] a [BrO 3 -
ID: 807757 • Letter: G
Question
Given the rate equation...
RATE = ([ Na2S2O3]/time) = k [I-]a [BrO3-]b [HCl]c
1A) You mix together in the proper manner the following:
10.0 mL of .0100 M Potassium Iodide
10.0 mL of .00100 M Sodium thiosulfate
10.0 mL of water
10.0 mL of .0400 M Potassium Bromate
10.0 mL of .100 M HCl
The time to turn blue is... 75 sec
1B) You also mix together in the proper manner the following:
10.0 mL of .0100 M Potassium Iodide
10.0 mL of .00100 M Sodium thiosulfate
10.0 mL of .0400 M Potassium Bromate
20.0 mL of .100 M HCl
The time to turn blue is... 20 sec
Calculate:
The Experimental value of exponent c..._______________ (a)
2) If the exponents a, b, and c have the values:
a = 1; b = 2; c = 2
CALCULATE:
Rate constant k for data in 1B...______________ (b)
3) You mix together in the proper manner the following VOLUMES:
0.0100 M Potassium iodide...9.7 mL
0.0010 M Sodium thiosulfate...6.0 mL
Distilled water...15.6 mL
0.0400 M Potassium Bromate...10.7 mL
0.100 M Hydrochloric acid...5.3 mL
Using the rate constant and rate equation from problem 2),
CALCULATE the time to turn blue...__________________ sec (c)
4) A plot of log Rate vs 1/T gives a best straight line which goes through....
1/T = 0.00300, log rate = -5.00
and 1/T = 0.00365, log rate = -6.00.
CALCULATE:
The Slope of the line..._____________ (d)
The Activation Energy (Ea) (Kj/mol)...________________(e)
Explanation / Answer
when you doubled the concentration of HCl the reaction went essentially 4X's faster
instead of taking 100 seconds, it took only 27 seconds
that's an effect of by the square
Rate = [2 X's as much HCl]^2
Rate = 4 X's faster
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