A eukaryotic chloride channel, when open, permits Cl^- ions to flow spontaneousl

Question

A eukaryotic chloride channel, when open, permits Cl^- ions to flow spontaneously across the membrane in the direction required to go toward equilibrium. Suppose that the extracellular concentration of Cl is 123 mM and the intracellular concentration is 4 mM. The membrane electrical potential (Delta V) is 0.06 V, inside negative relative to outside. Assume that RT = 2.479 KJ/mol, and F = 96.5 KJ/(V)(mol). Calculate the chemical potential term of Delta G_transport for transport of Cl^- ions into the cell. a. -331 b. -8.5 c. -6.97 d. 8.5 e. 331

Explanation / Answer

Chemical potential term iof Cl- ions is given by the formula, G = G0 + RTlnQ

For any spontaneous reaction, G is negative.

So, the Gtransport of Cl- ions is given by the formula, Gtransport = - (V+RTlnQ), V is membrane electric potential and Q is ratio of concentrations of Cl- ions

= - [(0.06) + (2.479) ln(123/4)]

= - [(0.06) + (2.479) ln(32.75)]

= -[(0.06) + (2.479) (3.42)]

= - [(0.06) + (8.47)]

= -8.53

So,the answer is option (b) -8.5

= - (

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