Molarity of citrus juice Va X Ma = (Vb X Mb) / 3 Test 1: 0.32 M Test 2: 0.34 M A

Question

Molarity of citrus juice

Va X Ma = (Vb X Mb) / 3 Test 1: 0.32 M

                                            Test 2: 0.34 M   

Average molarity of your citrus juice: 0.33 M

Class average reported for your citrus juice: 6.04 M

What was the molarity of your citrus juice? Show all calculations.

Using the molarity which you calculated, determine the grams per liter and the percentage of citric acid in your sample of citrus juice. Assume the juice has the same density as water. Show all calculations.

How far did you value for the % of your citrus juice deviate (differ) from the class average?

Explanation / Answer

molarity of your citrus juice= 0.33 M=0.33mol/L

1.mass of citric acid present=0.33gx192.124g/mol(molarmass)=63.40g

2.percentage of citric acid=63.40g/1000gx100=6.34% (since density of solution=water=1:1000ml=1000g)

3.% of your citrus juice deviation=observed

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.