Calculate equilibrium partial pressures of products and reactants Water gas The

Question

Calculate equilibrium partial pressures of products and reactants

Water gas The water-gas reaction is a source of hydrogen Passing steam over hot carbon produces a mixture of carbon monoxide and hydrogen: The value of Kc for the reaction at 1000 degree C is 300 x 10^-2. a. Calculate the equilibrium partial pressures of the products and reactants if PH2O = 0.442 atm and PCO = 5.000 atm at the start of the reaction. Assume that the carbon is in excess. b. Determine the equilibrium partial pressures of H2O, CO, and H2 after CO and H2 at 0.082 atm are added to the equilibrium mixture in part a.

Explanation / Answer

Kp = P(H2)P(CO) / P(H2O)
we know

Kp = Kc(RT)n

so

Kp = 0.003 X ( 0.0821 x 1273) = 0.313

initial pressure of H2O = 0.442 and CO = 5

let at equilbrium partial pressure are

pH2O = 0.442-x ; pCO = 5+x ; pH2 = x

so 0.313 = x (5+x) / 0.442-x

0.138 - 0.313x = 5x + x2

x2 + 5.313x -0.138 = 0

on solving

x = 0.025

so pH2O = 0.442-x = 0.417atm

; pCO = 5+x = 5.025 atm

; pH2 = x = 0.025 atm

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