Calculate the equilibrium concentration of each compound if 0.200 moles of H 2 a

Question

Calculate the equilibrium concentration of each compound if 0.200 moles of H2 and 0.330 moles of H2S are placed in a 3.00 liter container at 200. Kc = 14.2 for the reaction at this temperature. Assume an excess of sulfur is present.

[H2S] =   M [H2] =    M H2(g) + S(s) arrow H2S(g) Calculate t H2S(g) Calculate the equilibrium concentration of each compound if 0.200 moles of H2 and 0.330 moles of H2S are placed in a 3.00 liter container at 200½. Kc = 14.2 for the reaction at this temperature. Assume an excess of sulfur is present. [H2S] = M [H2] = M

Explanation / Answer

Initially

[H2] = 0.200/3 = 0.067 M

[H2S] = 0.330/3 = 0.11 M

At equilibrium

[H2]= 0.067 -x

[H2S] = 0.11 + x

Kc = [H2S]/[H2]

14.2 = 0.11+x/0.067 - x

14.2(0.067 - x) = 0.11 + x

x = 0.0553

[H2S] =0.11 + 0.0553 = 0.1653 M

[H2] = 0.067 - 0.0553 = 0.0117 M

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.