For the following reaction, K c = 255 at 1000 K. CO (g) + Cl2 (g) ? COCl2 (g) A

Question

For the following reaction, Kc = 255 at 1000 K.
CO (g) + Cl2 (g) ? COCl2 (g)
A reaction mixture initially contains a COconcentration of 0.1510 M and a Cl2concentration of 0.180 M at 1000 K.

Part A

What is the equilibrium concentration of CO at 1000 K?

Express your answer in molarity to three significant figures.

Part B

What is the equilibrium concentration of Cl2 at 1000 K?

Express your answer in molarity to three significant figures.

Part C

What is the equilibrium concentration of COCl2 at 1000 K?

Express your answer in molarity to three significant figures.

Explanation / Answer

the reaction is given as

CO + Cl2 ---> COCl2

KC = [COCl2] / [Cl2] [CO]

using ICE table

initial conc of CO , Cl2 and COCl2 are 0.151 , 0.18 , 0

change in conc of CO ,Cl2 and COCl2 are   -x , -x , x

equilibrium conc of CO , Cl2 and COCl2 are 0.151 -x , 0.18 - x , x

so

Kc = x / ( 0.151 - x ) ( 0.18-x)

255 = x / ( 0.151 - x ) ( 0.18-x)

solving we get

x= 0.1968 , 0.138

x should not be greater than 0.18

so

we get

x= 0.138

A)

eq conc of CO = 0.151 - x = 0.151 - 0.138 = 0.013 M

B)

eq conc of Cl2 = 0.18 - 0.138 = 0.042 M

C)

eq conc of COCl2 = x = 0.138 M

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