1. If 120mL of a 6 MNaOH solution is diluted to a final volume of 200mL , what i

Question

1. If 120mL of a 6 MNaOH solution is diluted to a final volume of 200mL , what is the resulting concentration of the solution?

Express your answer to one significant figure and include the appropriate units.

2. How many grams (of mass m) of glucose are in 165mL of a 5.50% (m/v) glucose solution?

Express your answer with the appropriate units.

3. You have a solution that is 18.5% (v/v) methyl alcohol. If the bottle contains 1.80L of solution, what is the volume (V) in milliliters of methyl alcohol?

Express your answer with the appropriate units.

4. A 6.00 % (m/v) NaCl solution contains 48.2g of NaCl. What is the total volume (V) of the solution in milliliters?

Express your answer with the appropriate units.

Explanation / Answer

1)

We will use the equation

moles in mix 1 = moles in mix 2 ... NOTE that the moles will remeain the same, we are just diluting!

M1*V1 = M2*V2

120ml*6M = 200 ml M2

M2 = 120/200 * 6= 3.6 M

2)

m/v %

then if 5% is mass of the total volume

0.055*165 ml = 9.07 grams of glucose in that volume!

3)18.5% V/V solution...

Total Volume = 1.8 L

Volume of methyl alcohol: 18.5 per 100 L

So... 0.185*1.8 = 0.333 L of methanol or 333 ml

4) 6% mass of NaCl per volume

then if we got 48.2g

% = mass/ volume *100%

6% = 48.2g /volume * 100%

0.06/48.2 = 1/Volume

Volume = 48.2/0.06 = 820 ml

NOTE: the % does not states if ml or Literes, use ml!

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