Help!! The reaction quotient (Q) for a system is 3.4 x 10^3. If the equilibrium

Question

Help!!

The reaction quotient (Q) for a system is 3.4 x 10^3. If the equilibrium constant (K) for the system is 1.2 x 10^-2, what will happen as the reaction mixture tries to approach equilibrium? a The equilibrium constant will increase until it equals the reaction quotient. b There will be a net gain in product(s). c There will be a net gain in reactant(s). d There will be a net gain in both product(s) and reactant(s). e The equilibrium constant will decrease until it equals the reaction quotient.

Explanation / Answer

If Kc = 1.2*10^-2

This means that in Equilibrium

Kc = [Products in Equilibrium]/[Reactants in equilibrium]

The reaction quotient is pretty similar to Kc

Q = [Actual Concentration of Products]/[Actual concentration of Reactants]

If Q>Kc

This favours the products!

Which is letter B

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