the tolerance is +/-2% Cyclopropane, C 3 H 6 , is a gas used as a general anesth

Question

the tolerance is +/-2%

Cyclopropane, C3H6, is a gas used as a general anesthetic. It undergoes a slow molecular rearrangement to propylene.

At a certain temperature, the following data were obtained relating concentration and rate.

Initial Concentration
of Cyclopropane(mol L-1) Rate of Formation
of Propylene (mol L-1 s-1) 0.050 2.95 x 10-5 0.100 5.90 x 10-5 0.150 8.85 x 10-5
Cyclopropane, C3H6, is a gas used as a general anesthetic. It undergoes a slow molecular rearrangement to propylene. At a certain temperature, the following data were obtained relating concentration and rate. What is the rate law for the reaction? What is the value of the rate constant? What is the correct units for this rate constant?

Explanation / Answer

(1) Let Rate = k[C3H6]^a

Note bracket () below denotes trial number


Rate(3)/Rate(1) = k[C3H6(3)]^a/k[C3H6(1)]^a

= ([C3H6(3)]/[C3H6(1)])^a


8.85 x 10^(-5)/2.95 x 10^(-5) = (0.150/0.050)^a

3 = 3^a => a = 1


Thus the rate law is: Rate = k[C3H6]


(2) Taking values from trial 1:

2.95 x 10^(-5) mol.L-1.s-1 = k x 0.050 mol.L-1


Rate constant k = 5.90 x 10^(-4) s-1

Value of k = 5.90 x 10^(-4)

Units = s-1

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