Assume that the binding of one molecule of epinephrine to a seven-transmembrane

Question

Assume that the binding of one molecule of epinephrine to a seven-transmembrane helix (7TM) receptor (also called the G protein-coupled receptor, or GPCR) results in the activation of 440 G? subunits. In addition, suppose that each activated adenylyl cyclase catalyzes the conversion of 20 ATP molecules to cAMP per second. (Assume that each G protein activates a single unique adenylyl cyclase.) Calculate the number of moles of cAMP that are produced per second. Enter your answer to at least two significant figures.

Assume that the binding of one molecule of epinephrine to a seven-transmembrane helix (7TM) receptor (also called the G protein-coupled receptor, or GPCR) results in the activation of 440 G? subunits. In addition, suppose that each activated adenylyl cyclase catalyzes the conversion of 20 ATP molecules to cAMP per second. (Assume that each G protein activates a single unique adenylyl cyclase.) Calculate the number of moles of cAMP that are produced per second. Enter your answer to at least two significant figures.

Assume that the binding of one molecule of epinephrine to a seven-transmembrane helix (7TM) receptor (also called the G protein-coupled receptor, or GPCR) results in the activation of 440 G? subunits. In addition, suppose that each activated adenylyl cyclase catalyzes the conversion of 20 ATP molecules to cAMP per second. (Assume that each G protein activates a single unique adenylyl cyclase.) Calculate the number of moles of cAMP that are produced per second. Enter your answer to at least two significant figures.
Assume that the binding of one molecule of epinephrine to a seven-transmembrane helix (7TM) receptor (also called the G protein-coupled receptor, or GPCR) results in the activation of 440 G? subunits. In addition, suppose that each activated adenylyl cyclase catalyzes the conversion of 20 ATP molecules to cAMP per second. (Assume that each G protein activates a single unique adenylyl cyclase.) Calculate the number of moles of cAMP that are produced per second. Enter your answer to at least two significant figures.

Explanation / Answer

No. of activated G subunits = No. of activated adenylyl cyclase = 440

1 adenylyl cyclase ----> 20 ATP -----> 20 cAMP

Thus, 440 adenylyl cyclase ----> 440 x 20 = 8800 cAMP/second

6.023 x 10^23 molecules = 1 mole

Thus,

8800 molecules/second = 1.461 x 10^26 moles/second or 1.46 E^26

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