I could really use some help with my Chem. Lab Report! Please! Molar Solubility

ID: 823778 • Letter: I

Question

I could really use some help with my Chem. Lab Report! Please!

Molar Solubility and solubility Product of Calcium Hydroxide:

1. Volume of Saturated Ca(OH)2 solution (mL) = 25.0 mL

2. Concentration of Standardized HCL solution (mol/L) = 0.053 mol/L

3. Buret reading, initial (mL) = 0.0 mL

4. Buret reading, final (mL) = 8.50 mL

5. Volume of HCL added (mL) = 8.50 mL

6. Moles of HCL added (mol) = (concentration of HCl)(Volume of HCl) = 4.51*10^-4

Now, I'm stuck. I need help finding the:

Moles of OH- in saturated solution (mol) ?

[OH-] equilibrium (mol/L) ?

[Ca2+] equilibrium (mol/L) ?

Molar solubility of Ca(OH)2 (mol/L) ?

Average molar solubility of Ca(OH)2 (mol/L) ?

Ksp of Ca(OH)2 ?

Average Ksp ?

Satandard deviation of Ksp ?

and the Relative Standard deviation of Ksp (%RSD) ?

Thank you!! Please show work so I can learn from this!

Using law of mass balance-

N1V1 = N2V2

2M1V1 = M2V2

2 x M1 x 25.0 = 0.053 x 8.50

M1 = 9.01 x 10^-3M = [Ca(OH)2]

moles of OH- = Molarity x volume x 2 = 9.01 x 10^-3 x 25 x 10^-3 x 2 = 4.505 x 10^-4 moles

[OH-] eqm = 2 x 9.01 x 10^-3M = 18.0 x 10^-3M

[Ca2+] eqm = 9.01 x 10^-3M

Molar solubility of Ca(OH)2 = 9.01 x 10^-3M

Ksp = s^3 = ( 9.01 x 10^-3M)^3 = 7.31 x 10^-7 M^3

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