a) use le chatelier\'s principle to explain the different colours found in the f

Question

a)

use le chatelier's principle to explain the different colours found in the following equilibrium reactions

CO2 + H2 <-> CO + H2O Volume is increased

KI <-> K+ + I- Pb(NO3)2 is added

4HCl + O2 <-> 2H2O +2Cl2 + 113kJ temperature is decreased

H2 +I2 <-> 2HI catalyst is added

b) The haze that tuns the sky over cities a brownish colour is primarily composed of nitrogen dioxide gas. Given the following equilibrium reaction, explain why the hazi is more common in summer than winter.

2NO2 {brown} <-> N2O4{colourless} + heat

Explanation / Answer

for first reaction there will be no change as no of moles on both sides are equal

for second reaction   Pb(NO3)2 (aq) + 2KI (aq) --> PbI2 (s) + 2KNO3 (aq) this will decrease concentration of kI so reaction shifts left to increase concentration of kI

for third reaction will shift to right side as we decrease the temperature reaction shifts to side for which tempratureWILL BE RAISED

for fourth reaction A catalyst will shift the equilibrium in the direction of the reaction that the catalyst promotes. If you add a catalyst that breaks HI bonds the H2+I2 phase will be increased, if you add a catalyst that promotes the binding of H to I the 2HI phase will be increased

b) in this reaction heat is released as temparature is more in summer the reaction shifts left

as temperatur is more in summer so No2 content will be more in summer so haze will be more in summmer

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