%3Cp%20class%3D%22c2%22%3ENote%3A%20%3Ca%20href%3D%0A%22https%3A%2F%2Fbrainmass.
ID: 826595 • Letter: #
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1. mol NaOH = 0.1332 * 15.8 = 2.10456 mmol
moles of HCOOH = 10 * M
10M = 2.10456
M = 0.210456 Molar
M = w/Mr * 1000/V
0.210456 = w/46.03 * 1000/(100)
w = 0.420912 gr
mass of 100 mL HCOOH solution = 100 * 1.02 = 102 gr
percentage by mass formic acids is
k = 0.420912/102 * 100%
k = 0.412%
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