Calculate the pOH of 118.36 mL of a buffer initially consisting of 0.1920 M C 6

Question

Calculate the pOH of 118.36 mL of a buffer initially consisting of 0.1920 M C6H5OHCOOH and 0.2753 M C6H5OHCOONa after addition of 0.0036 mol of NaOH. Assume that no volume change occurs after addition of the base. The Ka of C6H5OHCOOH is 1.05e-3 10.865 3.257 10.981 10.743 Calculate the pOH of 118.36 mL of a buffer initially consisting of 0.1920 M C6H5OHCOOH and 0.2753 M C6H5OHCOONa after addition of 0.0036 mol of NaOH. Assume that no volume change occurs after addition of the base. The Ka of C6H5OHCOOH is 1.05e-3 10.865 3.257 10.981 10.743 Calculate the pOH of 118.36 mL of a buffer initially consisting of 0.1920 M C6H5OHCOOH and 0.2753 M C6H5OHCOONa after addition of 0.0036 mol of NaOH. Assume that no volume change occurs after addition of the base. The Ka of C6H5OHCOOH is 1.05e-3 10.865 3.257 10.981 10.743

Explanation / Answer

3.257

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