An 48.22 g sample of aluminum is placed on a 57.05 g sample of copper initially

Question

An 48.22 g sample of aluminum is placed on a 57.05 g sample of copper initially at 116.57oC. If the heat is only transferred between the metals (with no loss to the surroundings) and the final temperature of both metals is 54.95oC, what is the inital temperature (in oC) of aluminum? An 48.22 g sample of aluminum is placed on a 57.05 g sample of copper initially at 116.57oC. If the heat is only transferred between the metals (with no loss to the surroundings) and the final temperature of both metals is 54.95oC, what is the inital temperature (in oC) of aluminum?

Explanation / Answer

heat lost by copper = heat gained by aluminium

let initial temp of Al = T

so 48.22*0.9*( 54.95-T) = 57.05*0.386*(116.57 - 54.95)

=> T = 23.68 degC

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