t Composition of inorganic Conjugate Acid-Base Pairs in Blood The following tabl

Question

t Composition of inorganic Conjugate Acid-Base Pairs in Blood The following table gives the constant values, K., for carbonic acid, H COh, and phosphoric acid, HaPOu Acid Kal H,PO 7.2 x 10-3 6.2x 10 42x10-13 At a pHof 7.40, what is the ratio of the molar concentrations of H,POe to HaPOa? Express your answer using two significant fgures. Hapoel 40-10 Submit Hants MLAnsamers Give Up Review Part incorrect Try Again: 4 attempts remaining Part D AtapH or 7.40, what is the ratio of the molar concentrations of CO, toHCO, Express your answer using two significant fgures. Submit Hints My Answers Give up Review Part Part E At apH of 7.40, what is the ratio of the molar concentratons of HCOs to H2COs? Express your answer using two significant figures. Hints My Answers Give Up Review Part Incorrect Try Again: 3 attempts remaining

Explanation / Answer

at pH=7.4 Ratio of [H2PO4-]/[H3PO4]=?

Ka1=7.2x10-3

pKa1=2.143

pH=pKa + log[H2PO4-]/[H3PO4]

7.4-2.143=log([H2PO4-]/[H3PO4])

antilog(5.257)=[H2PO4-]/[H3PO4]

[H2PO4-]/[H3PO4]=1.80E+5

Part D

at pH=7.4 Ratio of [CO32-]/[HCO3-]=?

Ka2=5.6E-11

pKa2=-log(5.6E-11)=10.25

pOH=pKa2 + log([CO32-]/[HCO3-])

7.4-10.25=log([CO32-]/[HCO3-])

-2.85=log([CO32-]/[HCO3-])

[CO32-]/[HCO3-]=antilog(-2.85)

[CO32-]/[HCO3-]=0.0014

Part E

At pH=7.4 , [HCO3-]/[H2CO3]=?

Ka1=4.3E-7

pKa1=-log(4.3E-7)=6.366

pH=pKa1+log([HCO3-]/[H2CO3])

7.4-6.366=log([HCO3-]/[H2CO3])

log[HCO3-]/[H2CO3]=1.033

[HCO3-]/[H2CO3]=antilog(1.0335)

[HCO3-]/[H2CO3]=10.80

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