Trial 1: 5 mmol Na2SO4 + 5 mmol CaCl2 was mixed Trial 2: 10 mmol Na2SO4 + 10 mmo

Question

Trial 1: 5 mmol Na2SO4 + 5 mmol CaCl2 was mixed

Trial 2: 10 mmol Na2SO4 + 10 mmol CaCl2 was Mixed

Trial 3: 20 + 10

Trial 4: 10 + 20

The last three CaSO4 masses should be the same except for a small water-mass difference Explain this statement. What should be the difference in CaSO4 mass between the Trial 1 and Trial 2? Which compound was in excess in Trial 3? Which compound was the limiting reagent in Trial 3? Which compound was in excess in Trial 4? Which compound was the limiting reagent in Trial 4?

Explanation / Answer

1. The reactants are in a 1:1 relationship, therefore 10 mmol of each will react in both cases, resulting in the same amount of product. Water is byproduct of this reaction, so the amount of water will change.

2. Twice as much (twice as many mmol going in and twice as much mmol coming out)

3. Na2SO4

4. CaCl2

5. CaCl2

6. Na2SO4

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