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Exercise 17.70 Use data from Appendix IIB to calculate the equilibrium constants

ID: 833273 • Letter: E

Question

Exercise 17.70

Use data from Appendix IIB to calculate the equilibrium constants at 25 ?C for each of the following reactions..

Part A

N2(g)+3H2(g)?2NH3(g)

Express your answer using two significant figures.

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Part B

Br2(g)+Cl2(g)?2BrCl(g)
?G?f for BrCl(g) is -1.0 kJ/mol

Express your answer using two significant figures.

PROBLEM #2

Relationship between free energy and the equilibrium constant

The standard free energy change, ?G?, and the equilibrium constant K for a reaction can be related by the following equation:

?G?=?RTlnK

where T is the Kelvin temperature and R is equal to 8.314 J/(mol?K).

Part B

Calculate the equilibrium constant for the following reaction at room temperature, 25 ?C:

N2(g)+O2(g)?2NO(g)

Express your answer numerically to three significant figures.

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K =

Explanation / Answer

N2(g)+3H2(g)?2NH3(g)

Express your answer using two significant figures.

K =

First find delta G by doing products - reactants

=
delta G = 2* (16.4) – 3(0)

delta G = -32.8 kJ/mol

or = -32800 J/ mole
delta G = -RT lnK

lnK = - delta G /RT

K= e^ - (-32800) /8.3145 *298
=e ^13.24
K = e^(16.48) = 5.62x10^5

Part B

Br2(g)+Cl2(g)?2BrCl(g)
?G?f for BrCl(g) is -1.0 kJ/mol

First find delta G by doing products - reactants

=
delta G = 2* (-1) – (0) – 3.14

delta G = -5.14 kJ/mol

or = -5140 J/ mole
delta G = -RT lnK

lnK = - delta G /RT

K= e^ - (-5140) /8.3145 *298
=e ^2.075
K = e^(2.075) = 7.96

K =

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