The proton mass is 1.007276amu , the neutron mass is 1.008665amu , and the elect

Question

The proton mass is 1.007276amu , the neutron mass is 1.008665amu , and the electron mass is5.48610?4amu .

a. What is the expected mass of a potassium-39 nucleus, based on the total mass of its protons and neutrons? (in amu)

b. The actual measured mass of a potassium-39 atom is 38.963707amu . What is the mass defect, deltam, for a potassium-39 nucleus? (in amu)

c. What is the binding energy for a potassium-39 nucleus? (in J/mol)

d.What is the binding energy, deltaE, for a potassium-39 nucleus in MeV/nucleon? Recall that 1 MeV=1.6010^13 J. (in MeV/nucleon)

Explanation / Answer

a.  expected mass of a potassium-39 nucleus = 19*1.007276 + 20*1.008665 + 19*0.0005486

= 39.3219674 amu

b. delta-m = 39.3219674 - 38.963707 = 0.3582604 amu

c. Binding Energy = 0.3582604 * 931.5 MeV = 333.7195626 MeV

= 333.7195626 *(10^6)*(6.022*10^23) 1.6 * 10^-19 J/mol

= 32154547295635.2 J/mol = 3.2454 X 10^10 Kj/mol

d.   Binding energy per nucleon = BE/39 = (333.7195626/39) = 8.55691 MeV/nucleon

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