What is the theoretical yield of 6,10 nylon? Reaction: 1,6 Hexanediamine Molar M

Question

What is the theoretical yield of 6,10 nylon?

Reaction:

1,6 Hexanediamine

Molar Mass = 116.20g/mol Density = .84 g/mL

Sebacoyl

Molar Mass 239.14g/mol Density = 1.12 g/mL

Mix 25 mL of 95% ethanol with 25 mL of water in a 150 beaker and set it aside for use later. In the hood: dissolve 1.0 mL of sebacoyl chloride in 25 mL of dichloromethane in a 50 mL beaker. Combine 5 drops of 1 M NaOH with 25 mL of 5% 1,6-hexanediamine solution. Tilt the beaker containing the dichloromethane solution and slowly pour it down the side of the beaker containing the 1,6'hexanediamine solution, taking care not to mix the layers. Use a piece of copper wire with a hook on the end to hook the film at the interface and draw it out of the beaker slowly. Wrap the film around a large test tube and slowly rotate the test tube to continuously draw the film out of the beaker and wind it around the test tube. Continue to wind the nylon until no more nylon rope can be drawn. Unwind the nylon into the aqueous ethanol and stir gently to wash it. Then decant the solvent, and lay the polymer on a paper towel to dry (blotting it between t towels will reduce the drying time). Weigh the nylon when dry. Place the remaining used chemicals in the beaker into the Used Organic cont found in the Used Chemical Hood. Figure 14-3. Winding the nylon film.

Explanation / Answer

moles sebacoyl chloride = 1 ml x 1.12 g/ml/239.14 g/mol = 0.005 moles

moles 1,6-hexanediamine = 25 ml x 0.05 x 0.840 g/ml/116.21 g/mol = 0.009 moles

Since moles of sebacoyl chloride is lower, this is the limiting reactant

Theoretical yield of Nylon 6,10 = 0.005 moles x 318.4 g/mol

                                                  = 1.592 g

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