1.Find the limiting reactant for each initial amount of reactants 4 Al(s) + 3 O2

Question

1.Find the limiting reactant for each initial amount of reactants

4 Al(s) + 3 O2(g) -> 2 Al2O3(s)

a. 1mol Al.1mol O2 c.16 mol Al . 13 mol O2

b.4mol Al , 2.6mol O2 d. 7.4mol Al 6.5 mol O2

2.what is the molarity of Cl- in each solution

a. 0.200 M NaCl

b. 0.150 M SrCl2

c 0.100 M AlCl3

3. Consider the unbalanced equation for the neutralization of Acetic Acid:

HC2H3O2(aq) + Ba(OH)2(aq)--> H2O(I) + Ba(C2H3O2)2 (aq)

balance the equation and determine how many moles of Ba(OH)2 are required to completely neutralize 0.461 mole of HC2H3O2

Explanation / Answer

1 a. O2

b. Al

c. O2

d.Al

2.a 0.2M

b 0.3M

c 0.3M

you have:
HC2H3O2 + Ba(OH)2 -> H2O + Ba(C2H3O2)2

Since Barium has a charge of +2 and Acetate has a charge of -1, you need 2 Acetate compounds to balance their charge.

Now, you need to count the elements on each side of the equation, to make sure they are balanced.
There are 6 H atoms on the left side, but there are 8 H atoms on the right side.
There are 2 atoms of C on the left side of the equation, but there are 4 on the right.
There are 4 atoms of O on the left side, but there are 5 on the right side.
And there are 2 atoms of Ba on both sides.

So, the H, C, and O need to be balanced.

By placing coefficients in front of compounds in the formula, you can easily balance the equation.

Balanced equation:
2 HC2H3O2 + Ba(OH)2 -> 2 H20 + Ba(C2H3O2)2


To check, again count the number of elements on each side of the equation.

There are 10 H atoms on both sides, 4 C atoms on both sides, 6 O atoms on both sides, and 2 Ba atoms on both sides.

For neutralizing 0.461 moles of acetic acid, we require 0.2305 moles of Ba(OH)2

3.

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