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1) Concentrated acetic acid has a molarity of 17.4. Describe the preparation of

ID: 835671 • Letter: 1

Question

1) Concentrated acetic acid has a molarity of 17.4. Describe the preparation of 400 mL of 0.35 M acetic acid solution.

2) How much 0.400 M acetic acid can be made from 5.00 mL of 20.0 M acetic acid solution?

3) A stock solution of 300 mM glycine was given to you. Describe the preparation of 5.0 mL solution containing 30 mM glycine.

4) how many grams of solid NaOH are required to prepare 500 mL of a 0.040 M solution? What is the concentration of this solution (express as % w/v)?

5) how many millilitres of 9 M NaCl are required to prepare 3.0 L of 0.003 M NaCl? express the final NaCl concentration in therms of:

(a) millimolar

(b) micromolar

Explanation / Answer

C=MV=400*0,35=140

2)M1V1=M2V2=0.400*V1=20*5

V1=100/0.4=250 ml ans

3)M1V1=M2V2=300*V1=30*5=V1=30/3000=0.1 mM ans

4)M=n/V

0.04=(w/m)/V

0.04=w/40*V

0.04=w/2*10^4

w=0.08*10^4=80 g ans

5)M1V1=M2V2=9*V1=0.003*3=V1=0.003*3/9=0.001 V ANS

a)M1V1=M2V2

9*0.001=M2*3

M2=0.009/3=0.003 *10^-3 mM

b)and in micromolar

M3=0.003*10^-6 ans