An alkane (A) with the formula C6H14 reacts with chlorine and light to form thre

Question

An alkane (A) with the formula C6H14 reacts with chlorine and light to form three compounds with the formula C6H13Cl: B, C, and D. Of these, only C and D undergo dehydrohalogenation with sodium ethoxide in ethanol to produce an alkene. Moreover, C and D yield the same alkene E (C6H12). Hydrogenation of E produces A. Treating E with HCl produces a compound (F) that is an isomer of B, C, and D. Treating F with Zn and acetic acid (replaces Cl with H) gives an alkane (G) which is isomeric with A. Propose structures for compounds A-G and write all the reactions.

Explanation / Answer

Had some trouble uploading the pic here. So please see this link for a detailed solution to your problem.

https://drive.google.com/file/d/0B2AXa0hD1wocSlc2RVpZbm5weHM/edit?usp=sharing

Hope it helps. Thanks!

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.