Write molecular and net ionic equation for each. Write the complex ion if one is

Question

Write molecular and net ionic equation for each. Write the complex ion if one is formed and no reaction if no rxn exists. Show work for any REDOX reactions.

Silver nitrate + copper(ii) sulfate

Silver nitrate + sodium hydroxide

Silver nitrate + ammonium iodide

Silver nitrate + barium chloride

Copper (ii) sulfate + sodium hydroxide

Copper (ii) sulfate + ammonium iodide

Copper (ii) sulfate + barium chloride

Sodium hydroxide + ammonium iodide

Sodium hydroxide + barium chloride

Ammonium iodide + barium chloride

Explanation / Answer

1. 2AgNO3(aq) + CuSO4(aq) ? Ag2SO4(s) + Cu(NO3)2(aq)

2.   AgNO3 (aq) + NaOH (aq) >> AgOH (s) + NaNO3 (aq)

Ag+ + NO3- + Na+ + OH- >> AgOH + Na+ + NO3-

Ag+ + OH- >> AgOH (s)

3. I(NH4)+AgNO3---> AgI + NH4NO3

AgI precipitates

4. 2 AgNO3 + BaCl2 = Ba(NO3)2 + 2 AgCl (s)

5. CuSO4 (aq) + 2 NaOH (aq) >> Cu(OH)2 (s) + Na2SO4 (aq)

Cu2+ + SO42- + 2 Na+ + 2 OH- >> Cu(OH)2 + 2 Na+ + SO42-

Cu2+ + 2OH- >> Cu(OH)2 (s)

6. The iodide ion reduces the aqueous Cu^2+ ions to Cu^+ which is stabilised by forming the very insoluble, off-white CuI as a precipitate.
Half equations: 2I^- ---> I2 + 2e and Cu^2+ + e ---> Cu^+
and (with excess iodide ions present): Cu^+(aq) + I^-(aq) ---> CuI(s)

7.   BaCl2(aq) + CuSO4(aq) => BaSO4(s) + CuCl2 (aq) . it is a double replacement reaction

8.   NH4I(aq) + NaOH(aq) ? NaI(aq) + NH3(g) + H2O(l)

9.   2NaOH + BaCl2 ---> 2NaCl + Ba(OH)2

Barium hydroxide is insoluble in water.

10. No reaction.

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