SHOW WORK FOR POINTS For one of the solutions you make up for this week\'s exper
ID: 840347 • Letter: S
Question
SHOW WORK FOR POINTS
For one of the solutions you make up for this week's experiment, 8.00 mL of 2.0E-3 M iron(III) nitrate solution is mixed with 1.00 mL of 2.0E-3 M potassium thiocyanate solution, 2.00 mL of 0.500 M nitric acid solution, and 9.00 mL of distilled water for a total volume of 20.00 mL. See line 2 in Table 1.
What is the initial concentration of Fe3+ ions in this solution, in other words, what is the concentration of Fe3+ ions before any reaction with the thiocyanate?
Initial concentration of Fe3+ = M
Calculate the mole fractions of Fe3+ and SCN- in this solution with respect to the total number of moles of Fe3+ and SCN-. This means, of course, that these two mole fractions should add up to 1.00.
Mole fraction of Fe3+ =
Mole fraction of SCN- =
Suppose that the mole fraction of Fe3+ in the iron(II) - thiocyanate solution was plotted against the absorbance of the solution at 450 nm. Suppose also that the maximum absorbance was established at a mole fraction of Fe3+ equal to 0.800 by plotting the two best straight lines through the data points. What is the stoichiometry of the complex formed between the Fe3+ and the thiocyanate?
Enter the answer as a whole number ratio; whole numbers separated by a colon (for example, 2:3, indicating a stoichiometry Fe2(SCN)3).
Stoichiometry of the complex formed between Fe3+ and SCN- =
***SHOW WORK FOR POINTS***
Explanation / Answer
0.001L x 0.002M Fe(NO3)2 = 2x10^-6 moles Fe3+ in Fe(NO3)3
moles Fe3+ / total volume of the solution = molarity of Fe 3+
2x10^-6moles Fe3+ / 0.02L = 1x10^-4M Fe3+ present
mole fraction Fe3+ = moles Fe3+ / total moles present
moles SCN- = 0.008L x 2x10^-3M = 1.6x10^-5moles SCN-
2x10^-6moles Fe3+ / (2x10^-6 + 1.6x10^-5) = 0.111
mole fraction SCN- = 0.889
if mole fraction of Fe3+ = 0.8 then the mole fraction of SCN- = 0.2
for 4:1 Fe3+:SCN-
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