Four solutions of unknown NaOH concentration are titrated with solutions of HCl.

Question

Four solutions of unknown NaOH concentration are titrated with solutions of HCl. The following table lists the volume of each unknown NaOH solution, the volume of HCl solution required to reach the endpoint, and the concentration of each HCl solution.

1- Calculate the concentration (in M) of the unknown NaOH solution in the first case.

0.2099M

2- Calculate the concentration (in M) of the unknown NaOH solution in the second case.

3- Calculate the concentration (in M) of the unknown NaOH solution in the third case.

4- Calculate the concentration (in M) of the unknown NaOH solution in the fourth case.

NaOH Volume (mL) HCl Volume (mL) [HCl](M) 3.00mL 9.77mL 0.2099M 19.00mL 10.54mL 0.1061M 14.00mL 10.85mL 0.0489M 32.00mL 40.18mL 0.1321M

Explanation / Answer

(1) M1V1=M2V2

    MI*3 = 9.77*0.2099

M1 = 0.6836 M

(2) M1V1=M2V2

    MI*19 = 10.54*0.1061

M1 = 0.05886 M

(3) M1V1=M2V2

    MI*14 = 10.58*0.0489

M1 = 0.037 M

(4) M1V1=M2V2

    MI*32 = 40.18*0.1321

M1 = 0.1659 M

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