Antibiotic-resistant bacteria have an enzyme, penicillinase, that catalyzes the

Question

Antibiotic-resistant bacteria have an enzyme, penicillinase, that catalyzes the decomposition of the antibiotic. The molecular mass of penicillinase is 31200 g/mol. The turnover number of the enzyme at 28 degree C is 2.00 * 103 s-1. If 5.89 ijg of penicillinase catalyzes the destruction of 3.38 mg of amoxicillin, an antibiotic with a molecular mass of 364 g/mol, in 24.6 seconds at 28 degree C, how many active sites does the enzyme have? Assume that the enzyme is fully saturated under the conditions described above.

Explanation / Answer

Convert everything to moles :-

Enzyme :-

5.89ug enzyme =( 5.89*10-6 )g/31200g/mol = 1.887*10-10 mol enzyme

Reactant(mox) :-

3.38mg amoxicillin = (3.38*10-3 g )/364g/mol = 9.286*10-6 mol reactant

Now, multiply moles of ENZYME with turnover value to get the moles of REACTANT converted PER SECOND, under saturation.

The product is: 1.887*10-10 mol enzyme * 2*103 sec-1 = 3.774*10-7 mol-sec-1

Multiplying by 24.6 seconds(The time given), we get :- 3.774*10-7 mol-sec-1 * 24.6 sec = 9.28 * 10-6 mol (Voila!)

Dividing the above number by the amount of reactant, and under conditions of total saturation, we get the number of active sites... TO BE 1.

There is a shorter way to do it, but I am bored, so I thought of doing it from scratch. Do please rate if you like it

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