B. STANDARDIZATION OF A CALCIUM HYDROXIDE SOLUTION: Write a balanced chemical eq

Question

B. STANDARDIZATION OF A CALCIUM HYDROXIDE SOLUTION: Write a balanced chemical equation for the reaction of hydrochloric acid with calcium hydroxide. Include states of reactants and products. 2HCI(aa) + Ca(OH)2(aa) ? CaCI2(s) + 2H2 O(aa) Data: Molarity of hydrochloric acid 0.050M 0.050M Volume of hydrochloric acid 21.00 mL 14:30mL Initial buret reading 0.00mL Final buret reading 21.00mL 14:30 mL Results: Moles hydrochloric acid used Moles calcium hydroxide used Volume calcium hydroxide used Concentration of calcium hydroxide Average Concentration of calcium hydroxide Calculations:

Explanation / Answer

According to equation 2 mole HCl is used for 1 mole Ca(OH)2

Molarity on trial one and trial 2 is 0.05 M

Volume is 21 and 14.3 respectively so concentration

trial 1 number of mole of HCl =(0.05/1000)*21 = 0.00105

trial 2 number of mole of HCl =(0.05/1000)*14.3 =0.000715

since 2 mole HCl reacting with 1 mole Ca(OH)2

so

number of mole of Ca(OH)2 used

trial 1 =  0.00105/2 = 0.0005moles

trial 2 = 0.000715/2 = 0.00035 moles

trial 1

toget  0.0005moles Ca(OH)2 = 74.09*0.0005 g is required

and You must have used certain amount of volume that will be ther in your procedure check here i am giving V

(check the volume added initially to conical flask)

Then concentration of Ca(OH)2= (0.0005/V)*1000 = ------Molar

trial 2

toget  0.0005moles Ca(OH)2 = 74.09* 0.00035 g is required

and You must have used certain amount of volume that will be ther in your procedure check here i am giving V

(check the volume added initially to conical flask)

Then concentration of Ca(OH)2= ( 0.00035/V)*1000 = ------Molar

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