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in biochemistry stock solutions are often prepared with concentrations higher th

ID: 844714 • Letter: I

Question

in biochemistry stock solutions are often prepared with concentrations higher than those that will be used in the experiment. aliquots of the stock solution are then diluted to the approporiate concentration. Consider the following situation. A stock protein solution was prepared with concentration of 10 mg/ml (solution A). An aliquot of 1.0 ml was removed from Solution A and diluted to a final volume of 10 ml (Solution B). An aliquot of 1.0 ml of solution B was removed and diluted to a final volume of 10 ml (solution C). this is an example of serial diluation.

Calculate the concentration of Solutions B and C. Show your work.

Explanation / Answer

Very important indeed for research :-

1. Original Stock = 10mg/ml

2. 1ml of stock (i.e. 10mg of the stuff) is taken and diluted to 10ml (i.e. 9ml of diluent like water or buffer is added to make the FINAL volume 10ml). Hence 10mg of stuff is present in 10ml now. Therefore concentration of B = 10mg/10ml = 1mg/ml (ANS)

3. 1ml of solution B (i.e. 1mg of the stuff) is taken and diluted to 10ml (i.e. 9ml of diluent like water or buffer is added to make the FINAL volume 10ml). Hence 1mg of stuff is present in 10ml now. Therefore concentration of C = 1mg/10ml =0.1mg/ml (ANS)

A drab mathematical way would be the formula Cinitial x Vinitial = Cfinal x Vfinal
(C= Concentration, V= final volume)

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Nice question