4a. (1 pts). Of the following terms, which one(s) apply to this transport system

Question

4a. (1 pts).   Of the following terms, which one(s) apply to this transport system? [indicate all correct possibilities]

                             Passive Transport     Active Transport   Group Translocation   ABC Transport

4b. (2 pts).   What is the immediate source of energy that drives this transport system and allows S. pneumoniae to scavenge low levels of glucose from its environment?

                                    ATP                     Glucose                  PEP                     PMF                 Glucose-6-phosphate

4c. (1 pts). If S. pneumoniae is growing in the presence of oxygen using glucose as its energy source, the metabolic pathway it is using would best be described as (choose one)

             Fermentation                        Anaerobic respiration           Aerobic respiration      Chemolithotrophy       

4d. (2 pts). What is the NET GAIN in ATP generated by S. pneumoniae when it transports and catabolizes one               molecule of glucose during aerobic growth?

cytoplamic membrane PEP ruvate inside outside EP A Pts Glucose tsI A Pyruvate A PtsA Glucose-6- BJ PtsB phosphate C- PtsC Hpr PtsH Figure 1. PTS transport of glucose. The Pin a circle represents a phosphate group.

Explanation / Answer

4. a)The primary bacterial system coupling the transport of carbohydrates (glucose) across the cytoplasmic membrane with their phosphorylation is a multiprotein phosphorelay called the phosphoenolpyruvate (PEP)-dependent phosphotransferase system (PTS).
The phosphoryl group on PEP is eventually transferred to the imported sugar via several proteins.Therefore group translocation is the term that applies to this transport system. The PTS system uses active transport to drive the pathway.

b) PTS method of glucose transport is a distinct method used by bacteria for glucose uptake. The PEP (phosphoenol pyruvate) is theimmediate source of energy that drives this transport system and allows S. pneumoniae to scavenge low levels of glucose from its environment.

c)If S. pneumoniae is growing in the presence of oxygen using glucose as its energy source, the metabolic pathway it is using would best be described as aerobic respiration. Aerobic respiration is the process of producing cellular energy involving oxygen.

d) Glycolysis yields 2 NADH and 2 ATP; the formation of acetyl CoA yields 2 NADH; the Krebs Cycle yields 6NADH, 2 ATP, 2 FADH2.
When the NADH and FADH2 from glycolysis and the Krebs cycle contribute their electrons to the electron transport chain, they yield a total of 34 ATP that were derived from NADH and FADH2.
Once 2 ATP are subtracted (the cost of moving NADH from glycolysis to the intermembrane space), the net yield is 36 ATP per molecule of glucose.

Therefore, the NET GAIN in ATP generated by S. pneumoniae when it transports and catabolizes one molecule of glucose during aerobic growth is 36ATP.

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