2. Assume that, in a population of birds, two alleles exist for tail color: red,

Question

2. Assume that, in a population of birds, two alleles exist for tail color: red, which is recessive, and blue, which is dominant. Out of a total population of 1000 birds, 640 have red tails, and 360 have blue tails. Assuming the gene for tail color in this population is in Hardy-Weinberg equilibrium answer the following: a. What is the frequency of the red allele? b. What is the frequency of the blue allele? c. What percentage of the birds are heterozygous? d. What percentage of the birds are blue homozygous?

Explanation / Answer

2)

a)rr=recessive=640BB & Br=dominant=360Total=1000Since in equilibrium: Q=q2& P=p2Q=q2=f(rr)=640/100=0.64q=(0.64)=0.8p=0.2Therefore the frequency of the red allele q=0.8

b)The frequency of the blue allele p=0.2

c)2pq=2*0.8*0.2=0.32= 32%

d)p2=.22=0.04= 4%

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