Chem help big points! Please help me figure out the formulas needed to answer th

Question

Chem help big points! Please help me figure out the formulas needed to answer these problems ? What is an aqueous solution? How many grams of sucrose (C12H22O11,342 g/mol) would be required to prepare 1.50 L of a 0.855 M sucrose solution? Suppose a water sample shows vanadium levels at50.00ppb. Assuming that the density of the water sample is 0.09982 g/mL, what is the concentration of vanadium in nanomoles per liter? To prepare 1.50 L of a solution that is 0.460 M sodium , how many mL of 1.66 M aqueous sodium sulfate should be diluted? Identity the acid and the base in the following reaction: CH3COOH(aq)+HPO4^2-(aq) CH2COO-(aq) +H2PO4-(aq)

Explanation / Answer

1. Aqueous Solution is solution when an solute is dissolve in water.

2. M = n / V, so n = M*V = 0.855*1.5 = 1.2825 mol => 1.2825 * 342 g = 438.615 grams

3. Per one litre, there is 0.9982 kg of water => 55.455 moles of H2O

50 ppb V => 50 moles per 1 billion moles of H2O (= 109)

Therefore, 50 nanomole of V per one mole of H2O

Hence, conc = 50*54.455 nanomoles per Litre = 2772.77 nanomoles per Litre

4. n = M*V 1.5*0.460 = 0.69 mol of Na+2

As sodium sulphate has 2 Na+2, we need half the amount of Na2SO4.

n = 0.69/2 = M*V, V = n/M = (0.69/2) / 1.66 = 0.21 L

5. As CH3COOH is losing H+, it is acid and hence HPO42- is base.

Cheers

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