Analysis of your DNA segment DNA coding strand: 5\' GGC AGC CTG CAG CCC TTG 3\'

Question

Analysis of your DNA segment DNA coding strand: 5' GGC AGC CTG CAG CCC TTG 3' (We give you this strand) mRNA strand: 5' GGC AGC CUG CAG CCC UUG 3' (You write this strand in the space provided) Note the only difference between the DNA coding strand and the mRNA strand is U replaces T, in the mRNA strand. Amino acid sequence: NH2 G S L Q L COOH (You write this sequence in the space provided) On the day, each student will receive a sheet of paper containing one segment of the human insulin DNA coding sequence. It will be either Segment 1, 2 or 3 (indicate which segment you have received on your proforma). Remember to record the full names of each member of your group on your proforma. We have divided every third nucleotide (letter) to separate the bases into codons. Determine the mRNA sequence from the DNA coding strand. Write out the mRNA sequence directly under the DNA sequence on the sheet that you have been given. Make sure that you put the appropriate prime number (5' or 3') at the beginning and at the end of the mRNA strand.

Explanation / Answer

Answer:

The DNA sequence that is given is:

DNA Coding Strand 5’ GGC AGC CTG CAG CCC TTG 3’ (sense strand or coding strand or non-template strand)

DNA Non Coding Strand 3’ CCG TCG GTC GGG AAC 5’ (Antisense strand or non-coding strand or template strand)

mRNA Strand 5’ GGC AGC CUG CAG CCC UUG 3’

Amino acid sequence from mRNA strand 5’ GGC AGC CUG CAG CCC UUG 3’ is: NH2- GSLQPL – COOH

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