The pedigree below shows a man affected with dominantly inherited Huntington dis

Question

The pedigree below shows a man affected with dominantly inherited Huntington disease (a rare, autosomal disorder).

Both of his children have elected pre-natal diagnosis, although they do not wish their status to be evaluated.

The Southern blot below has been typed for an RFLP with 2 morphs:

4.9kb fragment

or

3.7kb and 1.2kb fragments.

The restriction fragment locus is 4 map units away from the Huntington locus.

Calculate the chance that both fetuses will inherit the allele for Huntington.

(Assume the affected man is not homozygous for the rare Huntington allele.)

NOTE: Previously posted and incorrect answers include: 50%, 99%, or 25%

Explanation / Answer

Answer:

The father has Hh allele(Huntington disease) and mother has hh allele, so the gamete combinations are Hh, Hh, hh, hh

chance that both fetuses will inherit the allele for Huntington= (1/4*1/4)*100=1/16*100=6.25%

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