In Part A, we saw that ? G ?=?242.1 kJ for the hydrogenation of acetylene under
ID: 865562 • Letter: I
Question
In Part A, we saw that ?G?=?242.1 kJ for the hydrogenation of acetylene under standard conditions (all pressures equal to 1 atm and the common reference temperature 298 K). In Part B, you will determine the ?G for the reaction under a given set of nonstandard conditions.
t 25?C the reaction from Part A has a composition as shown in the table below.
Substance Pressure(atm)
C2H2(g) 3.65
H2(g) 4.95
C2H6(g) 5.25x10-2
What is the free energy change, ?G, in kilojoules for the reaction under these conditions?
Express your answer numerically in kilojoules.
Explanation / Answer
2H2 + C2H2 --> C2H6
?G = -RT(lnKp)
Kp = [C2H6] / [H2]^2[C2H2]
Kp = (0.0525) / (4.95)^2(3.65) = 5.87x10^-4
?G = -8.314kJ/mole-K x 298K x ln(8.54x10^-5)
?G = 23210.3kJ
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