In Part A, we saw that ?G?=?242.1 kJ for the hydrogenation of acetylene under st
ID: 973765 • Letter: I
Question
In Part A, we saw that ?G?=?242.1 kJ for the hydrogenation of acetylene under standard conditions (all pressures equal to 1 atm and the common reference temperature 298 K). In Part B, you will determine the ?G for the reaction under a given set of nonstandard conditions.
At 25 ?C the reaction from Part A has a composition as shown in the table below.
What is the free energy change, ?G, in kilojoules for the reaction under these conditions? Answer in kJ.
Pressure Substance(atm) C2H2(g) 3.55 H2(g) 5.05 C2He (g) 425x102Explanation / Answer
1) Convert G° to J = -242100
2) Solve for Q = pressure of products/pressure of reactants = 4.25 x 10^-2/(5.05^2) x (3.55) = 0.00046 atm
3) Plug everything into equation = -242100 + (8.314 x 298 x (ln 0.00046)) = -261138.36 J = -261.13 kJ
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