In Part A, we saw that AG degree = -242.1 kJ for the hydrogenation of acetylene

Question

In Part A, we saw that AG degree = -242.1 kJ for the hydrogenation of acetylene under standard conditions (all pressures equal to 1 atm and the common reference temperature 298 K). In Part B, you will determine the delta G for the reaction under a given set of nonstandard conditions. Part B At 25 degree C the reaction from Part A has a composition as shown in the table below. Substance Pressure (atm) C2H2(g) 4.95 H2(g) 4.65 C2H6(g) 425x10-2 What is the free energy change, delta G, in kilojoules for the reaction under these conditions? Express your answer numerically in kilojoules.

Explanation / Answer

voltage in the circuit, E0 = 80 V

Resistance, R = 13.1

Inductance, L = 2.21 H

Capaticance, C = 1.26 * 10^-6 F

at resonance, w = 1/sqrt(LC)

w = 0.6 * 1000 = 600 (approx)

Inductive reactance, XL = wL = 600 * 2.21 = 1326

maximum current in the circuit, i0 = E0/R

i0 = 80/13.1

i0 = 6.11 A

voltage across inductor, V = i0 XL = 6.11 * 1326

V = 8101.86 V

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