In Part A, we saw that G =242.1 kJ for the hydrogenation of acetylene under stan
ID: 907320 • Letter: I
Question
In Part A, we saw that G=242.1 kJ for the hydrogenation of acetylene under standard conditions (all pressures equal to 1 atm and the common reference temperature 298 K). In Part B, you will determine the G for the reaction under a given set of nonstandard conditions.
At 25 C the reaction from Part A has a composition as shown in the table below. Substance Pressure (atm) C2H2(g) 3.75 H2(g) 4.25 C2H6(g) 5.25×102 What is the free energy change, G, in kilojoules for the reaction under these conditions?
Explanation / Answer
We find Q of reaction , Q means reaction quotient
C2H2 (g) + 2H2 (g)----> C2H6 ( g )
Q = pC2H6 / ( pC2H2 x pH2^2) = ( 0.0525 / 3.75 x 4.25^2) = 0.0007750865
Now dG = dGo + RT ln K
dG = -242100 + ( 8.314 x 298) ln ( 0.0007750865) ( dGo units taken in J as we have R in J)
= -242100-17745.7
= -259846 J = - 259.85 KJ
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