For a first-order reaction, the half-life is constant. It depends only on the ra

Question

For a first-order reaction, the half-life is constant. It depends only on the rate constant k and not on the reactant concentration. It is expressed as t1/2 = 0.603/k For a second order reaction, the half-fife depends on the rate constant and the concentration of the reactant and so is expressed as t1/2=1/k[A]0 A certain first-order reaction (A rightarrow products) has a rate constant of 1.00 Times 10-2s-1 at 45 degree C. How many minutes does it take for the concentration of the reactant. |A|, to drop to 6.25% of the original concentration?

Explanation / Answer

t = 1/ k ln [A0/At]

= 1/1.00 *10-2 sec-1 ln [100/6.25]

= 277 sec

   = 4.62 min

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.