John is placing an Al(s) strip into a beaker containing a solution of Cu{2+}(aq)
ID: 870461 • Letter: J
Question
John is placing an Al(s) strip into a beaker containing a solution of Cu{2+}(aq), what will he observe once the strip has been submerged in the solution for a few minutes.
A)Al(s) will disolve to generate Al{3+}(aq), but Cu{2+}(aq) will not undergo any change.
b)Cu{2+}(aq) will deposit onto Al(s), but Al(s) will not undergo any change.
c)Al(s) will disolve to generate Al{3+}(aq), and the oxidation state of Cu{2+}(aq) will increase.
d)Cu{2+}(aq) will deposit onto Al(s),and Al{3+}(aq) will be genrated in the process.
e)Cu{2+}(aq) will deposit onto Al(s), and the oxidation state of Al(s) will be reduced.
Explanation / Answer
Actually this a REDOX reaction: The reaction occurs like this:
2Al(s) + 3Cu+2(aq) = 2Al+3 + 3Cu(s)
This reaction occurs like this:
2x(Al = Al+3 + 3e-) 2Al = 2Al+3
3x(Cu+2 + 2e- = Cu) 3Cu+2 = 3Cu
According to this, Al is reducting the Cu, and Cu oxidates Al. So the right would have to be option D
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