A cylinder contains oxygen gas (O 2 ) at a pressure of 2.40 atm. The volume is 5

Question

A cylinder contains oxygen gas (O2) at a pressure of 2.40 atm. The volume is 5.50L , and the temperature is 300K . Assume that the oxygen may be treated as an ideal gas. The oxygen is carried through the following processes:
(1) Heated at constant pressure from the initial state (state 1) to state 2, which has 460K.
(2) Cooled at constant volume to 250K (state 3).
(3) Compressed at constant temperature to a volume of 5.50L (state 4).
(4) Heated at constant volume to 300K , which takes the system back to state 1.

A. Calculate Q for each of the four processes.

B. Calculate W for each of the four processes.

Explanation / Answer

a. Q1 = 0.536 mol x 29.1 J/mol.K x 160 K = 2495.6 J (received)

V2 = V x T2/T = 5.50 L x 460K/300K = 8.433L

dV= V2-V = 2.933L

W1 = - p

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