Compound B -----> 2 Compound C 1. Calculate number of grams in 2.5 mol Compound

ID: 873372 • Letter: C

Question

Compound B -----> 2 Compound C

1. Calculate number of grams in 2.5 mol Compound B.

2. Calculate number of mol in 4.50 mL Compound B.

3. Convert 2.50 g of Compound B to moles of Compound C.

4. Calculate theoretical yield (in g) of Compound C if you started with 4.00 g of Compound B

5. Calculate percent yield of Compound B if you start with 4.00 g of Compound B and the actual yield is only 1.20 g Compound C.

Reagent MW Density Compound A 130 1.23 Catalyst 1000 5.68 Product MW Density Compound B 90 0.92

1. no. of moles = taken mass/ molar mass

so 2.5 mol = number of grams/90 g/mol

number of grams = 2.5 x 90 = 225 g

2. density = mass/volume

for B density = 0.92g/mL= mass/4.5mL

mass= 4.14g

so no.of moles = 4.14g/90g/mol = 0.046 mol

3. for the given reaction B = 2C

means 1 mole B produce 2 moles of C.

so 2.5g B means 2.5g/90g/ mol = 0.02778 mol produces 0.02778 x 2 =0.0556 moles of C

4. no. of moles of B = 4g/90g/mol = 0.044mol

it should produce 0.044 x 2 = 0.0889 moles of C.

means 0.0889 moles = yield in grams/ molar mass of C. So you need to give molar mass of C for theoretical yield.

5. percent yield = (actual yield/ theoretical yield) x100

Once molar mass is C is provided, theoretical yield is calculated anad hence percent yield.

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